Optimal. Leaf size=203 \[ \frac{2 c^4 \tan ^{-1}\left (\frac{\sqrt{a} \tan (e+f x)}{\sqrt{a \sec (e+f x)+a}}\right )}{a^{3/2} f}+\frac{12 \sqrt{2} c^4 \tan ^{-1}\left (\frac{\sqrt{a} \tan (e+f x)}{\sqrt{2} \sqrt{a \sec (e+f x)+a}}\right )}{a^{3/2} f}+\frac{8 c^4 \tan ^3(e+f x)}{3 f (a \sec (e+f x)+a)^{3/2}}-\frac{14 c^4 \tan (e+f x)}{a f \sqrt{a \sec (e+f x)+a}}-\frac{a c^4 \sin (e+f x) \tan ^4(e+f x) \sec ^2\left (\frac{1}{2} (e+f x)\right )}{f (a \sec (e+f x)+a)^{5/2}} \]
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Rubi [A] time = 0.286233, antiderivative size = 203, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.214, Rules used = {3904, 3887, 470, 582, 522, 203} \[ \frac{2 c^4 \tan ^{-1}\left (\frac{\sqrt{a} \tan (e+f x)}{\sqrt{a \sec (e+f x)+a}}\right )}{a^{3/2} f}+\frac{12 \sqrt{2} c^4 \tan ^{-1}\left (\frac{\sqrt{a} \tan (e+f x)}{\sqrt{2} \sqrt{a \sec (e+f x)+a}}\right )}{a^{3/2} f}+\frac{8 c^4 \tan ^3(e+f x)}{3 f (a \sec (e+f x)+a)^{3/2}}-\frac{14 c^4 \tan (e+f x)}{a f \sqrt{a \sec (e+f x)+a}}-\frac{a c^4 \sin (e+f x) \tan ^4(e+f x) \sec ^2\left (\frac{1}{2} (e+f x)\right )}{f (a \sec (e+f x)+a)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 3904
Rule 3887
Rule 470
Rule 582
Rule 522
Rule 203
Rubi steps
\begin{align*} \int \frac{(c-c \sec (e+f x))^4}{(a+a \sec (e+f x))^{3/2}} \, dx &=\left (a^4 c^4\right ) \int \frac{\tan ^8(e+f x)}{(a+a \sec (e+f x))^{11/2}} \, dx\\ &=-\frac{\left (2 a^3 c^4\right ) \operatorname{Subst}\left (\int \frac{x^8}{\left (1+a x^2\right ) \left (2+a x^2\right )^2} \, dx,x,-\frac{\tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{f}\\ &=-\frac{a c^4 \sec ^2\left (\frac{1}{2} (e+f x)\right ) \sin (e+f x) \tan ^4(e+f x)}{f (a+a \sec (e+f x))^{5/2}}-\frac{\left (a c^4\right ) \operatorname{Subst}\left (\int \frac{x^4 \left (10+8 a x^2\right )}{\left (1+a x^2\right ) \left (2+a x^2\right )} \, dx,x,-\frac{\tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{f}\\ &=\frac{8 c^4 \tan ^3(e+f x)}{3 f (a+a \sec (e+f x))^{3/2}}-\frac{a c^4 \sec ^2\left (\frac{1}{2} (e+f x)\right ) \sin (e+f x) \tan ^4(e+f x)}{f (a+a \sec (e+f x))^{5/2}}+\frac{c^4 \operatorname{Subst}\left (\int \frac{x^2 \left (48 a+42 a^2 x^2\right )}{\left (1+a x^2\right ) \left (2+a x^2\right )} \, dx,x,-\frac{\tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{3 a f}\\ &=-\frac{14 c^4 \tan (e+f x)}{a f \sqrt{a+a \sec (e+f x)}}+\frac{8 c^4 \tan ^3(e+f x)}{3 f (a+a \sec (e+f x))^{3/2}}-\frac{a c^4 \sec ^2\left (\frac{1}{2} (e+f x)\right ) \sin (e+f x) \tan ^4(e+f x)}{f (a+a \sec (e+f x))^{5/2}}-\frac{c^4 \operatorname{Subst}\left (\int \frac{84 a^2+78 a^3 x^2}{\left (1+a x^2\right ) \left (2+a x^2\right )} \, dx,x,-\frac{\tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{3 a^3 f}\\ &=-\frac{14 c^4 \tan (e+f x)}{a f \sqrt{a+a \sec (e+f x)}}+\frac{8 c^4 \tan ^3(e+f x)}{3 f (a+a \sec (e+f x))^{3/2}}-\frac{a c^4 \sec ^2\left (\frac{1}{2} (e+f x)\right ) \sin (e+f x) \tan ^4(e+f x)}{f (a+a \sec (e+f x))^{5/2}}-\frac{\left (2 c^4\right ) \operatorname{Subst}\left (\int \frac{1}{1+a x^2} \, dx,x,-\frac{\tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{a f}-\frac{\left (24 c^4\right ) \operatorname{Subst}\left (\int \frac{1}{2+a x^2} \, dx,x,-\frac{\tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{a f}\\ &=\frac{2 c^4 \tan ^{-1}\left (\frac{\sqrt{a} \tan (e+f x)}{\sqrt{a+a \sec (e+f x)}}\right )}{a^{3/2} f}+\frac{12 \sqrt{2} c^4 \tan ^{-1}\left (\frac{\sqrt{a} \tan (e+f x)}{\sqrt{2} \sqrt{a+a \sec (e+f x)}}\right )}{a^{3/2} f}-\frac{14 c^4 \tan (e+f x)}{a f \sqrt{a+a \sec (e+f x)}}+\frac{8 c^4 \tan ^3(e+f x)}{3 f (a+a \sec (e+f x))^{3/2}}-\frac{a c^4 \sec ^2\left (\frac{1}{2} (e+f x)\right ) \sin (e+f x) \tan ^4(e+f x)}{f (a+a \sec (e+f x))^{5/2}}\\ \end{align*}
Mathematica [A] time = 1.53023, size = 196, normalized size = 0.97 \[ \frac{c^4 \csc \left (\frac{1}{2} (e+f x)\right ) \sec \left (\frac{1}{2} (e+f x)\right ) \sec ^2(e+f x) \left (20 \cos (e+f x)-26 \cos (2 (e+f x))+28 \cos (3 (e+f x))+6 \left (\cos \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{3}{2} (e+f x)\right )\right )^2 \sqrt{\sec (e+f x)-1} \tan ^{-1}\left (\sqrt{\sec (e+f x)-1}\right )+36 \sqrt{2} \left (\cos \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{3}{2} (e+f x)\right )\right )^2 \sqrt{\sec (e+f x)-1} \tan ^{-1}\left (\frac{\sqrt{\sec (e+f x)-1}}{\sqrt{2}}\right )-22\right )}{12 a f \sqrt{a (\sec (e+f x)+1)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.28, size = 552, normalized size = 2.7 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 10.8018, size = 1616, normalized size = 7.96 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} c^{4} \left (\int - \frac{4 \sec{\left (e + f x \right )}}{a \sqrt{a \sec{\left (e + f x \right )} + a} \sec{\left (e + f x \right )} + a \sqrt{a \sec{\left (e + f x \right )} + a}}\, dx + \int \frac{6 \sec ^{2}{\left (e + f x \right )}}{a \sqrt{a \sec{\left (e + f x \right )} + a} \sec{\left (e + f x \right )} + a \sqrt{a \sec{\left (e + f x \right )} + a}}\, dx + \int - \frac{4 \sec ^{3}{\left (e + f x \right )}}{a \sqrt{a \sec{\left (e + f x \right )} + a} \sec{\left (e + f x \right )} + a \sqrt{a \sec{\left (e + f x \right )} + a}}\, dx + \int \frac{\sec ^{4}{\left (e + f x \right )}}{a \sqrt{a \sec{\left (e + f x \right )} + a} \sec{\left (e + f x \right )} + a \sqrt{a \sec{\left (e + f x \right )} + a}}\, dx + \int \frac{1}{a \sqrt{a \sec{\left (e + f x \right )} + a} \sec{\left (e + f x \right )} + a \sqrt{a \sec{\left (e + f x \right )} + a}}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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